## Vibrations and Dimensions

• 871
We have the vibrational frequencies of visible light ranging from red (lowest) to violet (highest). Then we have the higher and lower octaves of those vibrations, the infras and ultras. However, what isn't often related is that all the infras or ultras are their own range in a different octave. This means that visible red is of a higher vibration than all the infras, from infra-red to infra-violet. And that is because they are in different octaves.
The same is true of sounds in the octave notations.

However, one notable characteristic is that energy is not always linearly organised. For example, when looking at the relation between visible light and invisible light, instead of observing another red after the violet or another violet before the red, we find that, even using special instruments, the shades of colour do not exceed a certain spatial range. That is, the infra/ultra-red are close to the visible red, then followed by the infra/ultra-orange which are adjacent to the visible orange, and so on.

So, instead of a linear notation or arrangement that goes on forever, we seem to have a sort of transverse notation/arrangement where one octave seems to be next to the other and somehow inter-penetrating the others. Therefore, in roughly the same spatial range that we observe the visible light, we can by means of special instruments, observe multiple octaves of other scales of light.

So, that is how vibration seems to work. Now, in consideration of how the idea of dimensions seems to be getting a lot of traction. And, with the scientific understanding of how energy and vibration are fundamental to everything, is it possible that the multiple dimensions of which we attempt to conceive of have the same relation to our dimension that the lower and higher octave light frequencies have with visible light?
• 1.3k
Go to a physics forum and ask them.
• 2.5k
Not really sure what you're going on about. The energy of a photon is linearly related to its frequency always:

$E=hf$

If you have a cluster of photons of different frequencies, the energy is:

$E=h \sum_{i=1}^{N} f_i$

afaik the energy of a photon is always 'linearly organised' with respect to their frequency.
• 12.5k
Infra/ultra-orange??
• 871
The energy of a photon is linearly related to its frequency always:

Ok. But what is the relation between the stream of photons whose frequencies are in the 'visible' spectrum of light versus those in the infra and ultra scales of the spectrum?

And, are the different scales (the 'visible', the infra and the ultra) linearly organised with respect to each other?
• 871
Infra/ultra-orange??

I'm referring to the scales or spectrum in which those light frequencies belong to. Red or violet isn't the only 'light' frequency with an infra/ultra spectrum, is it?
• 585
However, one notable characteristic is that energy is not always linearly organised. For example, when looking at the relation between visible light and invisible light, instead of observing another red after the violet or another violet before the red, we find that, even using special instruments, the shades of colour do not exceed a certain spatial range. That is, the infra/ultra-red are close to the visible red, then followed by the infra/ultra-orange which are adjacent to the visible orange, and so on.

I'm not sure what you mean by that. Etymologically infrared means below red, that is of frequency below that of red. I have never seen infraorange being used, but it would mean of frequency below that of orange. "Ultra" means beyond, that is of greater frequency. This is just semantics. Infrared doesn't appear red to some instrument, ultraviolet doesn't appear violet to some instrument, they're just called that because they correspond to frequencies below that of red / above that of violet.

You seem to have the misconception that whenever there is for instance visible orange there is at the same time invisible ultrared, but ultrared would simply refer to light of frequency above that of red, so orange, yellow, green, blue, violet, ultraviolet, ..., ultrared is not invisible light that has independent existence and that is found when orange is found ...
• 2.5k
Ok. But what is the relation between the stream of photons whose frequencies are in the 'visible' spectrum of light versus those in the infra and ultra scales of the spectrum?

Photons don't care about the existence of our eyes.
• 12.5k

"Infrared" is a way of saying it's the longer wavelength, lower frequency end of the electromagnetic radiation spectrum, below red, which is one end of the visible light range. Likewise "ultraviolet" is a way of saying higher frequency, shorter wavelength electromagnetic radiation, beyond or above violet, the other end of the visible light range.

"Infra" is "below" --or in this case longer/lower. "Infraorange" would be red. "Ultra" is "beyond," or it's handy in this case to think of it as "above"--shorter/higher. "Ultraindigo" would be violet.
• 3.9k
multiple octaves

Radio waves are one form of EMF. ... Electromagnetic waves cover a vast frequency range from ELF Extremely low frequency of less than 1 Hz (cycles per second) up to hard gamma rays at over 300 EHz (EHz is 10 to the power 18 cycles per second). — google

If I have it right, that's around 48 octaves, but it's late and the bottle is empty. Anyway, the music of the spheres is a very old idea, and it turns out that matter has a wavelength too.

However, colour harmony as we humans know it works very differently and is related to the colour sensors of the eye which do not distinguish at all well the difference between a mixture of red and green wavelengths and the pure yellow wavelength. The way we see is as if the spectrum of wavelengths were joined to make a circle, as if the highest note on the piano lead to the lowest, which sounded' higher' ...

Well I know what I mean even if you don't!
• 114

Or maybe there are no other dimensions and this is it.
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