You are playing a game for money. There are two envelopes on a table.
You know that one contains $X and the other $2X, [but you do not
know which envelope is which or what the number X is]. Initially you
are allowed to pick one of the envelopes, to open it, and see that it
contains $Y . You then have a choice: walk away with the $Y or return
the envelope to the table and walk away with whatever is in the other
envelope. What should you do?
You could have X or 2X. If you have X and you switch then you get 2X but lose X so you gain X; so you get a +1 X. However, if you have 2X and switch then you gain X and lose 2X; so you get a -1 X. — Jeremiah
You just said the same exact thing i did — Jeremiah
It is the same thing, the math comes out exactly the same. — Jeremiah
I'm saying that if I have £10 then I either lose £5 by switching or gain £10. — Michael
My reasoning is:
I have £10. If X is 5 then I lose £5 by switching. If X is 10 then I gain £10 by switching.
So it's either -5 or +10. This is not the same. — Michael
Case one X = 5
If you have 2X and switch then you are left with 5 bucks. You had 10 and now you have 5. You got a -X.
Case two X = 10
If you have X and switch then you are left with 20 bucks. You had 10 and now you have 20. You got a +X.
Exactly what I said before. — Jeremiah
Case one x = 5. You lose 5 bucks.
You had 10 and now you have 5. Means you lost 5 and in that case X = 5. Therefore you got a -X.
Case two x = 10. You gain 10 bucks.
You had 10 and now you have 20. Means you gained 10 and in that case X=10. There you got a +X
The same outcome as you. — Jeremiah
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