• flannel jesus
    1.8k
    This riddle was not invented by me, but I have changed all the details to avoid it being easy to look up the canonical answer.

    There are 5 apartments in a row. In each apartment is a person with a unique hair color, nationality and preferred musical style. Every person is an artist in a unique medium. Each of the 5 front doors is colored a unique color. So, we're facing all 5 doors in front of us, and I give you the following information:

    1. The guy with Black hair listens to Classical Music
    2. The Photographer listens to Electronic Dance Music.
    3. The guy next door to the Indian guy listens to Classical Music.
    4. The middle door is painted Teal.
    5. The sculptor's door is painted pink.
    6. The red head is the right-hand neighbor (from our pov looking at the doors) of the Brunette.
    7. The man who listens to Jazz lives in the apartment next to the Brazilian.
    8. The oil painter lives next to the guy with grey hair.
    9. The red head has a purple door.
    10. The Digital Painter has blonde hair.
    11. The Watercolor Painter is Canadian.
    12. The oil painter lives in the first (leftmost) apartment.
    13. The guy with the Orange door likes Reggae.
    14. The Australian likes Hip Hop.

    So, whose door is White? And what medium does the Kenyan use for his art?

    This is deducible, but not easily. In fact all 5 properties of all 5 apartments are deducible.

  • bert1
    1.9k
    Might this help?

    2d564bd5e2862354b86a41e000b35ba0.jpg
  • flannel jesus
    1.8k
    I didn't use something like that, but it might be helpful for someone
  • Philosophim
    2.5k
    I wouldn't call this a riddle. This is a logic problem. They can be pretty fun to do, but there are countless online. https://www.brainzilla.com/logic/logic-grid/ if you want to join up and play a bunch.
  • bert1
    1.9k
    I'm impressed you did it without a grid. I suppose there are other ways to record the information.
  • flannel jesus
    1.8k
    I mean I used a hand-written "grid", just not one like that multi-layered one you posted. I had columns where i recorded information about each spot.

    It was really annoying when I got to the point where I could no longer straight-forwardly deduce any answers, though, and had to copy my grid by hand to test out making certain assumptions.
  • RussellAAccepted Answer
    1.7k
    So, whose door is White? And what medium does the Kenyan use for his art?flannel jesus

    The Brazilian's door is white. The Kenyan is a photographer.
  • RussellA
    1.7k
    Hey you got it!flannel jesus

    Not very elegantly, I'm afraid. Thanks for posting the logic problem.
  • Tarskian
    599
    I've had a go at this one:

    $ ./doors-artists.js
    final number of complete solutions:1
    ----
    door_index hair_color nationality musical_style door_color profession

    1 black Brazilian classical white oil_painter
    2 grey Indian jazz pink sculptor
    3 blonde Australian hiphop teal dig_painter
    4 brunette Canadian reggae orange waterc_painter
    5 red Kenyan elec_dance purple photographer

    For the aficionados, the javascript program:

    #!/usr/bin/env qjs
    
    //The following is what the French would call "le référentiel"
    
    var properties={
        "hair_color":["black","brunette","grey","red","blonde"],
        "nationality":["Indian","Brazilian","Canadian","Australian","Kenyan"],
        "musical_style":["classical","elec_dance","jazz","reggae","hiphop"],
        "door_color":["teal","pink","purple","orange","white"],
        "profession":["photographer","sculptor","oil_painter",
                        "dig_painter","waterc_painter"]
    };
    
    //constraints_type_1: 
    //It specifies that a particular property value must always
    //coexist with another property value
    
    var constraints_type_1 = [
        {"cix":1,"property_needle_1":"hair_color","value_needle_1":"black",
            "property_needle_2":"musical_style","value_needle_2":"classical"},
        {"cix":2,"property_needle_1":"musical_style","value_needle_1":"elec_dance",
            "property_needle_2":"profession","value_needle_2":"photographer"},
        {"cix":4,"property_needle_1":"door_index","value_needle_1":3,
            "property_needle_2":"door_color","value_needle_2":"teal"},
        {"cix":5,"property_needle_1":"profession","value_needle_1":"sculptor",
            "property_needle_2":"door_color","value_needle_2":"pink"},
        {"cix":9,"property_needle_1":"hair_color","value_needle_1":"red",
            "property_needle_2":"door_color","value_needle_2":"purple"},
        {"cix":10,"property_needle_1":"profession","value_needle_1":"dig_painter",
            "property_needle_2":"hair_color","value_needle_2":"blonde"},
        {"cix":11,"property_needle_1":"profession","value_needle_1":"waterc_painter",
            "property_needle_2":"nationality","value_needle_2":"Canadian"},
        {"cix":12,"property_needle_1":"profession","value_needle_1":"oil_painter",
            "property_needle_2":"door_index","value_needle_2":1},
        {"cix":13,"property_needle_1":"door_color","value_needle_1":"orange",
            "property_needle_2":"musical_style","value_needle_2":"reggae"},
        {"cix":14,"property_needle_1":"nationality","value_needle_1":"Australian",
            "property_needle_2":"musical_style","value_needle_2":"hiphop"}
    ];
    
    //check constraints of type 1
    
    function isValidForType1(solution) {
        for(let assignment of solution) {
            for(let constraint of constraints_type_1) {
                let property_needle_1=constraint["property_needle_1"];
                let value_needle_1=constraint["value_needle_1"];
                let property_needle_2=constraint["property_needle_2"];
                let value_needle_2=constraint["value_needle_2"];
                //the assignment must have both properties assigned
                //for a constraint violation to even be possible
                if(!assignment.hasOwnProperty(property_needle_1)) continue;
                if(!assignment.hasOwnProperty(property_needle_2)) continue;
                //check for: value1 correct but value2 wrong
                if(assignment[property_needle_1]==value_needle_1 && 
                        assignment[property_needle_2]!==value_needle_2)
                    return false;
                //check for: value2 correct but value1 wrong
                if(assignment[property_needle_2]==value_needle_2 && 
                        assignment[property_needle_1]!==value_needle_1)
                    return false;
            }       
        }    
        return true;
    }
    
    //constraints_type_2
    //It specifies that a particular property value must always coexist
    //with a property value of a neigbor
    
    var constraints_type_2 = [
        {"cix":3,"property_needle":"nationality","value_needle":"Indian",
                "property_neighbor":"musical_style","value_neighbor":"classical"},
        {"cix":7,"property_needle":"nationality","value_needle":"Brazilian",
                "property_neighbor":"musical_style","value_neighbor":"jazz"},
        {"cix":8,"property_needle":"hair_color","value_needle":"grey",
                "property_neighbor":"profession","value_neighbor":"oil_painter"}
    ];
    
    // utility function: find neighbor of assignment by door index
    
    function findNeighborByDoorIndex(solution,door_index) {
        for(let assignment of solution) {
            if(assignment["door_index"]==door_index)
                return assignment;
        }
        //not found
        //This should never happen. Maybe throw an exception of sorts?
        return null;
    }
    
    //check constraints of type 2
    
    function isValidForType2(solution) {
        for(let constraint of constraints_type_2) {
            let property_needle=constraint["property_needle"];
            let value_needle=constraint["value_needle"];
            let property_neighbor=constraint["property_neighbor"];
            let value_neighbor=constraint["value_neighbor"];
            for(let assignment of solution) {
                //the assignment must have the property assigned
                if(!assignment.hasOwnProperty(property_needle)) continue;
                //the assignment must have the value assigned to the property
                if(assignment[property_needle]!==value_needle) continue;
                //retrieve door_index from assignment
                let door_index=assignment["door_index"];
                //we assume that we will not find a valid neighbor
                let foundValidNeighbor=false;
                //check left neighbor, if applicable
                if(door_index>1) {
                    let assignmentLeftNeighbor=findNeighborByDoorIndex(solution,door_index-1);
                    if(!assignmentLeftNeighbor.hasOwnProperty(property_neighbor)) continue;
                    if(assignmentLeftNeighbor[property_neighbor]==value_neighbor) {
                        foundValidNeighbor=true;
                    }
                }
                //check right neighbor, if applicable
                if(door_index<5) {
                    let assignmentRightNeighbor=findNeighborByDoorIndex(solution,door_index+1);
                    if(!assignmentRightNeighbor.hasOwnProperty(property_neighbor)) continue;
                    if(assignmentRightNeighbor[property_neighbor]==value_neighbor) {
                        foundValidNeighbor=true;
                    }
                }
                if(!foundValidNeighbor) {
                    return false;
                }
            }        
        }
        return true;
    }
    
    //check constraints of type 3
    //cix=6, Special case.
    //this function only checks:
    //"The red head is the right-hand neighbor of the Brunette."
    
    function isValidForType3(solution) {
        for(let assignment of solution) {
            //the assignment must have the property assigned
            if(!assignment.hasOwnProperty("hair_color")) continue;
            //the assignment must have the value assigned to the property
            if(assignment["hair_color"]!=="brunette") continue;
            //we found the brunette
            //check that there is a right-hand neighbor
            var door_index=assignment["door_index"];
            //Brunette cannot be assigned to door 5
            if(door_index==5) return false;
            //find right-hand neighbor
            var assignmentRightNeighbor=findNeighborByDoorIndex(solution,door_index+1);
            //The right-hand neighbor must be the red head
            if(assignmentRightNeighbor["hair_color"]!=="red") return false;
        }
        return true;
    }
    
    //validate solution
    
    function isValid(solution)
    {
        let validForType1=isValidForType1(solution);
        if(!validForType1) return false;
        let validForType2=isValidForType2(solution);
        if(!validForType2) return false;
        let validForType3=isValidForType3(solution);
        if(!validForType3) return false;
        return true;
    }
    
    //permutator
    
    const permutator = (inputArr) => {
      let result = [];
    
      const permute = (arr, m = []) => {
        if (arr.length === 0) {
          result.push(m)
        } else {
          for (let i = 0; i < arr.length; i++) {
            let curr = arr.slice();
            let next = curr.splice(i, 1);
            permute(curr.slice(), m.concat(next))
         }
       }
     }
     permute(inputArr)
     return result;
    }
    
    //for debugging purposes
    
    function output(label,structure) {
        console.log(label+":"+JSON.stringify(structure));
    }
    
    //initial solution space
    
    var solutionSpace=[
        [{"door_index":1},{"door_index":2},{"door_index":3},
                   {"door_index":4},{"door_index":5}]
    ];
    
    //iterate over the properties
    for(let property of Object.keys(properties)) {
        let propertyValues=properties[property];
        let permutations=permutator(propertyValues);
        let newSolutionSpace=[];
        //iterate over the permutations of the property values
        for(let permutation of permutations) {
            //cartesian multiplication of existing solutions with
            //new permutations
            for(let solution of solutionSpace) {    
                let newSolution=[];
                for (let i = 0; i < solution.length; i++) {
                    let assignment=solution[i];
                    let newAssignment={...assignment};
                    newAssignment[property]=permutation[i];
                    newSolution.push(newAssignment);
                }
                //verify if the solution satisfies all constraints
                if(isValid(newSolution)){
                    newSolutionSpace.push(newSolution);
                }
            }
        }
        //the new solution space now replaces the existing one
        solutionSpace=newSolutionSpace;
    }
    
    console.log("final number of complete solutions:"+solutionSpace.length);
    
    //output the solutions
    
    function pad(str){
        let pad=Array(15).join(' ');
        return (str + pad).substring(0, pad.length);
    }
    console.log("----");
    let headerPrintedAlready=false;
    for(let solution of solutionSpace) {
        for(let assignment of solution) {
            let line="";
            for(let key of Object.keys(assignment)) {
                line=line+pad(assignment[key]);
            }
            if(!headerPrintedAlready) {
                let header="";
                for(let key of Object.keys(assignment)) {
                    header=header+pad(key);
                }
                console.log(header);
                console.log("");
                headerPrintedAlready=true;
            }
            console.log(line);
        }
        console.log("----");
    }
    
  • RussellA
    1.7k
    For the aficionados, the javascript program:Tarskian

    ickzoopg2uyk8960.png
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